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BaseRepresentation
bin100110001001…
…011100101001
3200211001122122
4212021130221
510030001134
6554201025
7151000004
oct46113451
920731578
1010000169
115710303
123423175
1320c197a
14148453b
15d2802e
hex989729

10000169 has 2 divisors, whose sum is σ = 10000170. Its totient is φ = 10000168.

The previous prime is 10000141. The next prime is 10000189. The reversal of 10000169 is 96100001.

It can be divided in two parts, 10000 and 169, that multiplied together give a square (1690000 = 13002).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7398400 + 2601769 = 2720^2 + 1613^2 .

It is an emirp because it is prime and its reverse (96100001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10000169 - 212 = 9996073 is a prime.

It is a super-2 number, since 2×100001692 = 200006760057122, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (10000139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000084 + 5000085.

It is an arithmetic number, because the mean of its divisors is an integer number (5000085).

Almost surely, 210000169 is an apocalyptic number.

It is an amenable number.

10000169 is a deficient number, since it is larger than the sum of its proper divisors (1).

10000169 is an equidigital number, since it uses as much as digits as its factorization.

10000169 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

The square root of 10000169 is about 3162.3043813017. The cubic root of 10000169 is about 215.4446826612. Note that the first 3 decimals are identical.

The spelling of 10000169 in words is "ten million, one hundred sixty-nine", and thus it is an aban number.