1000133113 has 4 divisors (see below), whose sum is σ = 1143009280. Its totient is φ = 857256948.

The previous prime is 1000133111. The next prime is 1000133149. The reversal of 1000133113 is 3113310001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1000133113 - 2¹ = 1000133111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1000133093 and 1000133102.

It is not an unprimeable number, because it can be changed into a prime (1000133111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71438073 + ... + 71438086.

It is an arithmetic number, because the mean of its divisors is an integer number (285752320).

Almost surely, 2^1000133113 is an apocalyptic number.

It is an amenable number.

1000133113 is a deficient number, since it is larger than the sum of its proper divisors (142876167).

1000133113 is an equidigital number, since it uses as much as digits as its factorization.

1000133113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 142876166.

The product of its (nonzero) digits is 27, while the sum is 13.

The square root of 1000133113 is about 31624.8812329786. The cubic root of 1000133113 is about 1000.0443690314.

Adding to 1000133113 its reverse (3113310001), we get a palindrome (4113443114).

The spelling of 1000133113 in words is "one billion, one hundred thirty-three thousand, one hundred thirteen".