1000473 has 4 divisors (see below), whose sum is σ = 1333968. Its totient is φ = 666980.

The previous prime is 1000457. The next prime is 1000507. The reversal of 1000473 is 3740001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3740001 = 3 ⋅1246667.

It is a cyclic number.

It is not a de Polignac number, because 1000473 - 2⁴ = 1000457 is a prime.

It is a D-number.

1000473 is a lucky number.

It is a plaindrome in base 7.

It is not an unprimeable number, because it can be changed into a prime (1000403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166743 + ... + 166748.

It is an arithmetic number, because the mean of its divisors is an integer number (333492).

2^1000473 is an apocalyptic number.

It is an amenable number.

1000473 is a deficient number, since it is larger than the sum of its proper divisors (333495).

1000473 is an equidigital number, since it uses as much as digits as its factorization.

1000473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 333494.

The product of its (nonzero) digits is 84, while the sum is 15.

The square root of 1000473 is about 1000.2364720405. The cubic root of 1000473 is about 100.0157641814.

Adding to 1000473 its reverse (3740001), we get a palindrome (4740474).

The spelling of 1000473 in words is "one million, four hundred seventy-three", and thus it is an aban number.