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10010010053 is a prime number
BaseRepresentation
bin10010101001010010…
…01010000111000101
3221211121121012100002
421110221022013011
5131000030310203
64333141131045
7503025452531
oct112451120705
927747535302
1010010010053
11427743178a
121b343b9a85
13c36ab3794
146ad60abc1
153d8bd8d88
hex254a4a1c5

10010010053 has 2 divisors, whose sum is σ = 10010010054. Its totient is φ = 10010010052.

The previous prime is 10010010013. The next prime is 10010010071. The reversal of 10010010053 is 35001001001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7695149284 + 2314860769 = 87722^2 + 48113^2 .

It is a cyclic number.

It is not a de Polignac number, because 10010010053 - 220 = 10008961477 is a prime.

It is a super-2 number, since 2×100100100532 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10010010013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005005026 + 5005005027.

It is an arithmetic number, because the mean of its divisors is an integer number (5005005027).

Almost surely, 210010010053 is an apocalyptic number.

It is an amenable number.

10010010053 is a deficient number, since it is larger than the sum of its proper divisors (1).

10010010053 is an equidigital number, since it uses as much as digits as its factorization.

10010010053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 11.

Adding to 10010010053 its reverse (35001001001), we get a palindrome (45011011054).

The spelling of 10010010053 in words is "ten billion, ten million, ten thousand, fifty-three".