100110000112181 has 2 divisors, whose sum is σ = 100110000112182. Its totient is φ = 100110000112180.

The previous prime is 100110000112163. The next prime is 100110000112183. The reversal of 100110000112181 is 181211000011001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92936039631556 + 7173960480625 = 9640334^2 + 2678425^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100110000112181 is a prime.

It is a super-2 number, since 2×100110000112181² (a number of 29 digits) contains 22 as substring.

Together with 100110000112183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100110000112183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055000056090 + 50055000056091.

It is an arithmetic number, because the mean of its divisors is an integer number (50055000056091).

Almost surely, 2^{100110000112181} is an apocalyptic number.

It is an amenable number.

100110000112181 is a deficient number, since it is larger than the sum of its proper divisors (1).

100110000112181 is an equidigital number, since it uses as much as digits as its factorization.

100110000112181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16, while the sum is 17.

Adding to 100110000112181 its reverse (181211000011001), we get a palindrome (281321000123182).

The spelling of 100110000112181 in words is "one hundred trillion, one hundred ten billion, one hundred twelve thousand, one hundred eighty-one".