100111121210909 has 2 divisors, whose sum is σ = 100111121210910. Its totient is φ = 100111121210908.

The previous prime is 100111121210857. The next prime is 100111121210911. The reversal of 100111121210909 is 909012121111001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89457490490809 + 10653630720100 = 9458197^2 + 3263990^2 .

It is a cyclic number.

It is not a de Polignac number, because 100111121210909 - 2¹² = 100111121206813 is a prime.

It is a super-3 number, since 3×100111121210909³ (a number of 43 digits) contains 333 as substring.

It is a Sophie Germain prime.

Together with 100111121210911, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100111121710909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055560605454 + 50055560605455.

It is an arithmetic number, because the mean of its divisors is an integer number (50055560605455).

Almost surely, 2^{100111121210909} is an apocalyptic number.

It is an amenable number.

100111121210909 is a deficient number, since it is larger than the sum of its proper divisors (1).

100111121210909 is an equidigital number, since it uses as much as digits as its factorization.

100111121210909 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 29.

The spelling of 100111121210909 in words is "one hundred trillion, one hundred eleven billion, one hundred twenty-one million, two hundred ten thousand, nine hundred nine".