Base | Representation |
---|---|
bin | 10110110000111100111101… |
… | …010110000001111110011101 |
3 | 111010111110211110102001022022 |
4 | 112300330331112001332131 |
5 | 101110340313011304433 |
6 | 552534542522025525 |
7 | 30042335002515404 |
oct | 2660747526017635 |
9 | 433443743361268 |
10 | 100121011822493 |
11 | 299a10a002a532 |
12 | b2901583482a5 |
13 | 43b34a8b4973c |
14 | 1aa1c506a263b |
15 | b8959d4de698 |
hex | 5b0f3d581f9d |
100121011822493 has 2 divisors, whose sum is σ = 100121011822494. Its totient is φ = 100121011822492.
The previous prime is 100121011822483. The next prime is 100121011822529. The reversal of 100121011822493 is 394228110121001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100120896517849 + 115304644 = 10006043^2 + 10738^2 .
It is a cyclic number.
It is not a de Polignac number, because 100121011822493 - 210 = 100121011821469 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100121011822423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50060505911246 + 50060505911247.
It is an arithmetic number, because the mean of its divisors is an integer number (50060505911247).
Almost surely, 2100121011822493 is an apocalyptic number.
It is an amenable number.
100121011822493 is a deficient number, since it is larger than the sum of its proper divisors (1).
100121011822493 is an equidigital number, since it uses as much as digits as its factorization.
100121011822493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 35.
Adding to 100121011822493 its reverse (394228110121001), we get a palindrome (494349121943494).
The spelling of 100121011822493 in words is "one hundred trillion, one hundred twenty-one billion, eleven million, eight hundred twenty-two thousand, four hundred ninety-three".
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