Base | Representation |
---|---|
bin | 101110100111110110… |
… | …0111101100000010101 |
3 | 100120102122010211120012 |
4 | 1131033230331200111 |
5 | 3120022041343013 |
6 | 113554541450005 |
7 | 10143050101610 |
oct | 1351754754025 |
9 | 316378124505 |
10 | 100121434133 |
11 | 39508a37396 |
12 | 174a2570905 |
13 | 9597a19366 |
14 | 4bbb231177 |
15 | 290ec251a8 |
hex | 174fb3d815 |
100121434133 has 8 divisors (see below), whose sum is σ = 114436330368. Its totient is φ = 85809496464.
The previous prime is 100121434129. The next prime is 100121434213. The reversal of 100121434133 is 331434121001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 100121434133 - 22 = 100121434129 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 100121434099 and 100121434108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100121434433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 666641 + ... + 802902.
It is an arithmetic number, because the mean of its divisors is an integer number (14304541296).
Almost surely, 2100121434133 is an apocalyptic number.
It is an amenable number.
100121434133 is a deficient number, since it is larger than the sum of its proper divisors (14314896235).
100121434133 is an equidigital number, since it uses as much as digits as its factorization.
100121434133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1479283.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 100121434133 its reverse (331434121001), we get a palindrome (431555555134).
The spelling of 100121434133 in words is "one hundred billion, one hundred twenty-one million, four hundred thirty-four thousand, one hundred thirty-three".
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