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100323211133 = 195280169007
BaseRepresentation
bin101110101101110111…
…0101011011101111101
3100120221200211011120102
41131123232223131331
53120430220224013
6114030550330445
710151050140005
oct1353356533575
9316850734512
10100323211133
1139601923442
121753a059a25
1395ca776432
144bd9d57005
1529227d0d58
hex175bbab77d

100323211133 has 4 divisors (see below), whose sum is σ = 105603380160. Its totient is φ = 95043042108.

The previous prime is 100323211123. The next prime is 100323211139. The reversal of 100323211133 is 331112323001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100323211133 - 216 = 100323145597 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100323211139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2640084485 + ... + 2640084522.

It is an arithmetic number, because the mean of its divisors is an integer number (26400845040).

Almost surely, 2100323211133 is an apocalyptic number.

It is an amenable number.

100323211133 is a deficient number, since it is larger than the sum of its proper divisors (5280169027).

100323211133 is an equidigital number, since it uses as much as digits as its factorization.

100323211133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5280169026.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 100323211133 its reverse (331112323001), we get a palindrome (431435534134).

The spelling of 100323211133 in words is "one hundred billion, three hundred twenty-three million, two hundred eleven thousand, one hundred thirty-three".

Divisors: 1 19 5280169007 100323211133