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10034331030121 is a prime number
BaseRepresentation
bin1001001000000100110010…
…1111001001001001101001
31022112021100210010021121111
42102001030233021021221
52303400302220430441
633201412534110321
72053646035315156
oct222011457111151
938467323107544
1010034331030121
1132195992aa092
1211608791ab3a1
1357a3058b5928
1426994285b22d
15126038dd0081
hex9204cbc9269

10034331030121 has 2 divisors, whose sum is σ = 10034331030122. Its totient is φ = 10034331030120.

The previous prime is 10034331030043. The next prime is 10034331030221. The reversal of 10034331030121 is 12103013343001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9460053518400 + 574277511721 = 3075720^2 + 757811^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10034331030121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10034331030092 and 10034331030101.

It is not a weakly prime, because it can be changed into another prime (10034331030221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5017165515060 + 5017165515061.

It is an arithmetic number, because the mean of its divisors is an integer number (5017165515061).

Almost surely, 210034331030121 is an apocalyptic number.

It is an amenable number.

10034331030121 is a deficient number, since it is larger than the sum of its proper divisors (1).

10034331030121 is an equidigital number, since it uses as much as digits as its factorization.

10034331030121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 10034331030121 its reverse (12103013343001), we get a palindrome (22137344373122).

The spelling of 10034331030121 in words is "ten trillion, thirty-four billion, three hundred thirty-one million, thirty thousand, one hundred twenty-one".