1010001113333 has 2 divisors, whose sum is σ = 1010001113334. Its totient is φ = 1010001113332.

The previous prime is 1010001113299. The next prime is 1010001113357. The reversal of 1010001113333 is 3333111000101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 626768305969 + 383232807364 = 791687^2 + 619058^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1010001113333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1010001113833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505000556666 + 505000556667.

It is an arithmetic number, because the mean of its divisors is an integer number (505000556667).

Almost surely, 2^{1010001113333} is an apocalyptic number.

It is an amenable number.

1010001113333 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010001113333 is an equidigital number, since it uses as much as digits as its factorization.

1010001113333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1010001113333 its reverse (3333111000101), we get a palindrome (4343112113434).

The spelling of 1010001113333 in words is "one trillion, ten billion, one million, one hundred thirteen thousand, three hundred thirty-three".