10100320033 has 4 divisors (see below), whose sum is σ = 10179850240. Its totient is φ = 10020789828.

The previous prime is 10100320001. The next prime is 10100320063. The reversal of 10100320033 is 33002300101.

10100320033 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10100320033 - 2⁵ = 10100320001 is a prime.

It is a super-2 number, since 2×10100320033² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10100319995 and 10100320022.

It is not an unprimeable number, because it can be changed into a prime (10100320063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39764913 + ... + 39765166.

It is an arithmetic number, because the mean of its divisors is an integer number (2544962560).

Almost surely, 2^10100320033 is an apocalyptic number.

It is an amenable number.

10100320033 is a deficient number, since it is larger than the sum of its proper divisors (79530207).

10100320033 is an equidigital number, since it uses as much as digits as its factorization.

10100320033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79530206.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 10100320033 its reverse (33002300101), we get a palindrome (43102620134).

The spelling of 10100320033 in words is "ten billion, one hundred million, three hundred twenty thousand, thirty-three".