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10103320131 = 33367773377
BaseRepresentation
bin10010110100011010…
…00110111001000011
3222002010011211200220
421122031012321003
5131142422221011
64350313114123
7505240542552
oct113215067103
928063154626
1010103320131
114315073a53
121b5b6b8943
13c50224248
146bbb79d99
153e1ebb506
hex25a346e43

10103320131 has 4 divisors (see below), whose sum is σ = 13471093512. Its totient is φ = 6735546752.

The previous prime is 10103320061. The next prime is 10103320151. The reversal of 10103320131 is 13102330101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10103320131 - 211 = 10103318083 is a prime.

It is a super-2 number, since 2×101033201312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10103320131.

It is not an unprimeable number, because it can be changed into a prime (10103320151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1683886686 + ... + 1683886691.

It is an arithmetic number, because the mean of its divisors is an integer number (3367773378).

Almost surely, 210103320131 is an apocalyptic number.

10103320131 is a deficient number, since it is larger than the sum of its proper divisors (3367773381).

10103320131 is an equidigital number, since it uses as much as digits as its factorization.

10103320131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3367773380.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10103320131 its reverse (13102330101), we get a palindrome (23205650232).

The spelling of 10103320131 in words is "ten billion, one hundred three million, three hundred twenty thousand, one hundred thirty-one".

Divisors: 1 3 3367773377 10103320131