10110000853 has 4 divisors (see below), whose sum is σ = 10110315820. Its totient is φ = 10109685888.

The previous prime is 10110000821. The next prime is 10110000869. The reversal of 10110000853 is 35800001101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 35800001101 = 23 ⋅1556521787.

It can be written as a sum of positive squares in 2 ways, for example, as 3862995409 + 6247005444 = 62153^2 + 79038^2 .

It is a cyclic number.

It is not a de Polignac number, because 10110000853 - 2⁵ = 10110000821 is a prime.

It is the 100549-th Hogben number.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10110000853.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10110000353) by changing a digit.

It is a nontrivial repunit in base 100548.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103068 + ... + 175621.

It is an arithmetic number, because the mean of its divisors is an integer number (2527578955).

Almost surely, 2^10110000853 is an apocalyptic number.

It is an amenable number.

10110000853 is a deficient number, since it is larger than the sum of its proper divisors (314967).

10110000853 is an equidigital number, since it uses as much as digits as its factorization.

10110000853 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 314966.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 10110000853 its reverse (35800001101), we get a palindrome (45910001954).

The spelling of 10110000853 in words is "ten billion, one hundred ten million, eight hundred fifty-three", and thus it is an aban number.