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101100113 is a prime number
BaseRepresentation
bin1100000011010…
…10101001010001
321001020102021122
412001222221101
5201340200423
614010532025
72335223342
oct601525121
9231212248
10101100113
1152083014
1229a37015
1317c3a46a
14d5da0c9
158d208c8
hex606aa51

101100113 has 2 divisors, whose sum is σ = 101100114. Its totient is φ = 101100112.

The previous prime is 101100089. The next prime is 101100133. The reversal of 101100113 is 311001101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98644624 + 2455489 = 9932^2 + 1567^2 .

It is a cyclic number.

It is not a de Polignac number, because 101100113 - 26 = 101100049 is a prime.

It is a super-2 number, since 2×1011001132 = 20442465697225538, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101100113.

It is not a weakly prime, because it can be changed into another prime (101100133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550056 + 50550057.

It is an arithmetic number, because the mean of its divisors is an integer number (50550057).

Almost surely, 2101100113 is an apocalyptic number.

It is an amenable number.

101100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101100113 is an equidigital number, since it uses as much as digits as its factorization.

101100113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 8.

The square root of 101100113 is about 10054.8551953770. The cubic root of 101100113 is about 465.8547703294.

Adding to 101100113 its reverse (311001101), we get a palindrome (412101214).

The spelling of 101100113 in words is "one hundred one million, one hundred thousand, one hundred thirteen".