Base | Representation |
---|---|
bin | 11101011011001000110… |
… | …10111111011111010001 |
3 | 10120122120110211121202221 |
4 | 32231210122333133101 |
5 | 113031013020040303 |
6 | 2052240431541041 |
7 | 133020401106121 |
oct | 16554432773721 |
9 | 3518513747687 |
10 | 1011002111953 |
11 | 35a8443764a9 |
12 | 143b3268a781 |
13 | 7444c782562 |
14 | 36d0b706c81 |
15 | 1b4725c14bd |
hex | eb646bf7d1 |
1011002111953 has 2 divisors, whose sum is σ = 1011002111954. Its totient is φ = 1011002111952.
The previous prime is 1011002111941. The next prime is 1011002112011. The reversal of 1011002111953 is 3591112001101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 781654028544 + 229348083409 = 884112^2 + 478903^2 .
It is a cyclic number.
It is not a de Polignac number, because 1011002111953 - 217 = 1011001980881 is a prime.
It is not a weakly prime, because it can be changed into another prime (1011002111753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505501055976 + 505501055977.
It is an arithmetic number, because the mean of its divisors is an integer number (505501055977).
Almost surely, 21011002111953 is an apocalyptic number.
It is an amenable number.
1011002111953 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011002111953 is an equidigital number, since it uses as much as digits as its factorization.
1011002111953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 270, while the sum is 25.
The spelling of 1011002111953 in words is "one trillion, eleven billion, two million, one hundred eleven thousand, nine hundred fifty-three".
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