Base | Representation |
---|---|

bin | 11101011011001000110… |

… | …10111111100000000010 |

3 | 10120122120110211121211202 |

4 | 32231210122333200002 |

5 | 113031013020041002 |

6 | 2052240431541202 |

7 | 133020401106221 |

oct | 16554432774002 |

9 | 3518513747752 |

10 | 1011002112002 |

11 | 35a844376543 |

12 | 143b3268a802 |

13 | 7444c78259c |

14 | 36d0b706cb8 |

15 | 1b4725c1502 |

hex | eb646bf802 |

1011002112002 has 4 divisors (see below), whose sum is σ = 1516503168006. Its totient is φ = 505501056000.

The previous prime is 1011002111953. The next prime is 1011002112011. The reversal of 1011002112002 is 2002112001101.

Adding to 1011002112002 its reverse (2002112001101), we get a palindrome (3013114113103).

1011002112002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 735753933121 + 275248178881 = 857761^2 + 524641^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252750527999 + ... + 252750528002.

Almost surely, 2^{1011002112002} is an apocalyptic number.

1011002112002 is a deficient number, since it is larger than the sum of its proper divisors (505501056004).

1011002112002 is an equidigital number, since it uses as much as digits as its factorization.

1011002112002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 505501056003.

The product of its (nonzero) digits is 8, while the sum is 11.

The spelling of 1011002112002 in words is "one trillion, eleven billion, two million, one hundred twelve thousand, two".

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