Base | Representation |
---|---|
bin | 10010110101010100… |
… | …11001111001011001 |
3 | 222002122122000201011 |
4 | 21122222121321121 |
5 | 131201404001103 |
6 | 4351145453521 |
7 | 505363040362 |
oct | 113252317131 |
9 | 28078560634 |
10 | 10111000153 |
11 | 431943a081 |
12 | 1b621a12a1 |
13 | c519b2b37 |
14 | 6bcbb8b69 |
15 | 3e29d6d6d |
hex | 25aa99e59 |
10111000153 has 2 divisors, whose sum is σ = 10111000154. Its totient is φ = 10111000152.
The previous prime is 10111000073. The next prime is 10111000171. The reversal of 10111000153 is 35100011101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10063500489 + 47499664 = 100317^2 + 6892^2 .
It is an emirp because it is prime and its reverse (35100011101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10111000153 - 29 = 10110999641 is a prime.
It is not a weakly prime, because it can be changed into another prime (10111000183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055500076 + 5055500077.
It is an arithmetic number, because the mean of its divisors is an integer number (5055500077).
Almost surely, 210111000153 is an apocalyptic number.
It is an amenable number.
10111000153 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111000153 is an equidigital number, since it uses as much as digits as its factorization.
10111000153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15, while the sum is 13.
Adding to 10111000153 its reverse (35100011101), we get a palindrome (45211011254).
The spelling of 10111000153 in words is "ten billion, one hundred eleven million, one hundred fifty-three", and thus it is an aban number.
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