Base | Representation |
---|---|
bin | 10110111111010110000111… |
… | …101010001100010111100111 |
3 | 111021000000211210101100021112 |
4 | 112333112013222030113213 |
5 | 101223041441340200012 |
6 | 555013201133535235 |
7 | 30203651363615036 |
oct | 2677260752142747 |
9 | 437000753340245 |
10 | 101110101100007 |
11 | 2a24260a1550aa |
12 | b40b99434451b |
13 | 4455845848a6c |
14 | 1ad7a7da3871d |
15 | ba518be4e122 |
hex | 5bf587a8c5e7 |
101110101100007 has 2 divisors, whose sum is σ = 101110101100008. Its totient is φ = 101110101100006.
The previous prime is 101110101099881. The next prime is 101110101100103. The reversal of 101110101100007 is 700001101011101.
It is a strong prime.
It is an emirp because it is prime and its reverse (700001101011101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101110101100007 - 28 = 101110101099751 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101110101099964 and 101110101100000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101110101100507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555050550003 + 50555050550004.
It is an arithmetic number, because the mean of its divisors is an integer number (50555050550004).
Almost surely, 2101110101100007 is an apocalyptic number.
101110101100007 is a deficient number, since it is larger than the sum of its proper divisors (1).
101110101100007 is an equidigital number, since it uses as much as digits as its factorization.
101110101100007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7, while the sum is 14.
Adding to 101110101100007 its reverse (700001101011101), we get a palindrome (801111202111108).
The spelling of 101110101100007 in words is "one hundred one trillion, one hundred ten billion, one hundred one million, one hundred thousand, seven".
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