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101111110099469 is a prime number
BaseRepresentation
bin10110111111010111000011…
…110011001110001000001101
3111021000010110002222211022222
4112333113003303032020031
5101223101023141140334
6555013445220145125
730204015365150321
oct2677270363161015
9437003402884288
10101111110099469
112a242a87765358
12b4100162381a5
1344559768b7272
141ad7b37a49981
15ba51ea80bd2e
hex5bf5c3cce20d

101111110099469 has 2 divisors, whose sum is σ = 101111110099470. Its totient is φ = 101111110099468.

The previous prime is 101111110099457. The next prime is 101111110099471. The reversal of 101111110099469 is 964990011111101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99651544083844 + 1459566015625 = 9982562^2 + 1208125^2 .

It is a cyclic number.

It is not a de Polignac number, because 101111110099469 - 220 = 101111109050893 is a prime.

It is a super-2 number, since 2×1011111100994692 (a number of 29 digits) contains 22 as substring.

Together with 101111110099471, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101111110099409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555555049734 + 50555555049735.

It is an arithmetic number, because the mean of its divisors is an integer number (50555555049735).

Almost surely, 2101111110099469 is an apocalyptic number.

It is an amenable number.

101111110099469 is a deficient number, since it is larger than the sum of its proper divisors (1).

101111110099469 is an equidigital number, since it uses as much as digits as its factorization.

101111110099469 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17496, while the sum is 44.

The spelling of 101111110099469 in words is "one hundred one trillion, one hundred eleven billion, one hundred ten million, ninety-nine thousand, four hundred sixty-nine".