Base | Representation |
---|---|
bin | 11101011011110000001… |
… | …11011110011101001010 |
3 | 10120200102111121010011102 |
4 | 32231320013132131022 |
5 | 113032202112241414 |
6 | 2052333314101402 |
7 | 133031522516642 |
oct | 16557007363512 |
9 | 3520374533142 |
10 | 1011332540234 |
11 | 35a9a3943125 |
12 | 14400527a862 |
13 | 744a3075253 |
14 | 36d3d55b522 |
15 | 1b4915e0ede |
hex | eb781de74a |
1011332540234 has 8 divisors (see below), whose sum is σ = 1549275380928. Its totient is φ = 494907413260.
The previous prime is 1011332540177. The next prime is 1011332540287. The reversal of 1011332540234 is 4320452331101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 1011332540197 and 1011332540206.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5379428312 + ... + 5379428499.
It is an arithmetic number, because the mean of its divisors is an integer number (193659422616).
Almost surely, 21011332540234 is an apocalyptic number.
1011332540234 is a deficient number, since it is larger than the sum of its proper divisors (537942840694).
1011332540234 is a wasteful number, since it uses less digits than its factorization.
1011332540234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10758856860.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 1011332540234 its reverse (4320452331101), we get a palindrome (5331784871335).
The spelling of 1011332540234 in words is "one trillion, eleven billion, three hundred thirty-two million, five hundred forty thousand, two hundred thirty-four".
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