Base | Representation |
---|---|
bin | 101111001000000001… |
… | …1101000101110010011 |
3 | 100200012212202120100002 |
4 | 1132100003220232103 |
5 | 3124224441321042 |
6 | 114254031120215 |
7 | 10211600220341 |
oct | 1362003505623 |
9 | 320185676302 |
10 | 101201120147 |
11 | 39a12437486 |
12 | 1774407306b |
13 | 970a606a1a |
14 | 4c807a2991 |
15 | 29748e7132 |
hex | 17900e8b93 |
101201120147 has 2 divisors, whose sum is σ = 101201120148. Its totient is φ = 101201120146.
The previous prime is 101201120107. The next prime is 101201120159. The reversal of 101201120147 is 741021102101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101201120147 - 220 = 101200071571 is a prime.
It is not a weakly prime, because it can be changed into another prime (101201120107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600560073 + 50600560074.
It is an arithmetic number, because the mean of its divisors is an integer number (50600560074).
Almost surely, 2101201120147 is an apocalyptic number.
101201120147 is a deficient number, since it is larger than the sum of its proper divisors (1).
101201120147 is an equidigital number, since it uses as much as digits as its factorization.
101201120147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 101201120147 its reverse (741021102101), we get a palindrome (842222222248).
The spelling of 101201120147 in words is "one hundred one billion, two hundred one million, one hundred twenty thousand, one hundred forty-seven".
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