1012012120993 has 2 divisors, whose sum is σ = 1012012120994. Its totient is φ = 1012012120992.

The previous prime is 1012012120969. The next prime is 1012012121047. The reversal of 1012012120993 is 3990212102101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 998174833569 + 13837287424 = 999087^2 + 117632^2 .

It is a cyclic number.

It is not a de Polignac number, because 1012012120993 - 2⁵ = 1012012120961 is a prime.

It is not a weakly prime, because it can be changed into another prime (1012012120963) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506006060496 + 506006060497.

It is an arithmetic number, because the mean of its divisors is an integer number (506006060497).

Almost surely, 2^{1012012120993} is an apocalyptic number.

It is an amenable number.

1012012120993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012012120993 is an equidigital number, since it uses as much as digits as its factorization.

1012012120993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 31.

The spelling of 1012012120993 in words is "one trillion, twelve billion, twelve million, one hundred twenty thousand, nine hundred ninety-three".