1012122112033 has 2 divisors, whose sum is σ = 1012122112034. Its totient is φ = 1012122112032.

The previous prime is 1012122111943. The next prime is 1012122112063. The reversal of 1012122112033 is 3302112212101.

1012122112033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1010933724304 + 1188387729 = 1005452^2 + 34473^2 .

It is an emirp because it is prime and its reverse (3302112212101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1012122112033 - 2¹³ = 1012122103841 is a prime.

It is a super-2 number, since 2×1012122112033² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1012122112033.

It is not a weakly prime, because it can be changed into another prime (1012122112063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506061056016 + 506061056017.

It is an arithmetic number, because the mean of its divisors is an integer number (506061056017).

Almost surely, 2^{1012122112033} is an apocalyptic number.

It is an amenable number.

1012122112033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012122112033 is an equidigital number, since it uses as much as digits as its factorization.

1012122112033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1012122112033 its reverse (3302112212101), we get a palindrome (4314234324134).

The spelling of 1012122112033 in words is "one trillion, twelve billion, one hundred twenty-two million, one hundred twelve thousand, thirty-three".