1013111303 has 2 divisors, whose sum is σ = 1013111304. Its totient is φ = 1013111302.

The previous prime is 1013111287. The next prime is 1013111321. The reversal of 1013111303 is 3031113101.

It is a happy number.

1013111303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1013111303 - 2⁴ = 1013111287 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1013111503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506555651 + 506555652.

It is an arithmetic number, because the mean of its divisors is an integer number (506555652).

Almost surely, 2^1013111303 is an apocalyptic number.

1013111303 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013111303 is an equidigital number, since it uses as much as digits as its factorization.

1013111303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27, while the sum is 14.

The square root of 1013111303 is about 31829.4094038831. The cubic root of 1013111303 is about 1004.3514715631.

Adding to 1013111303 its reverse (3031113101), we get a palindrome (4044224404).

The spelling of 1013111303 in words is "one billion, thirteen million, one hundred eleven thousand, three hundred three".