1013511444403 has 4 divisors (see below), whose sum is σ = 1073129764680. Its totient is φ = 953893124128.

The previous prime is 1013511444401. The next prime is 1013511444427. The reversal of 1013511444403 is 3044441153101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1013511444403 - 2¹ = 1013511444401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1013511444401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29809160113 + ... + 29809160146.

It is an arithmetic number, because the mean of its divisors is an integer number (268282441170).

Almost surely, 2^{1013511444403} is an apocalyptic number.

1013511444403 is a deficient number, since it is larger than the sum of its proper divisors (59618320277).

1013511444403 is an equidigital number, since it uses as much as digits as its factorization.

1013511444403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59618320276.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 1013511444403 its reverse (3044441153101), we get a palindrome (4057952597504).

The spelling of 1013511444403 in words is "one trillion, thirteen billion, five hundred eleven million, four hundred forty-four thousand, four hundred three".