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1014132022403 = 6595115377053
BaseRepresentation
bin11101100000111101111…
…10101001110010000011
310120221122121022112202012
432300132332221302003
5113103420244204103
62053515200443135
7133161064650353
oct16603676516203
93527577275665
101014132022403
113611000a7555
121446669194ab
137482b050886
1437127288b63
151b5a72772d8
hexec1efa9c83

1014132022403 has 4 divisors (see below), whose sum is σ = 1014147465408. Its totient is φ = 1014116579400.

The previous prime is 1014132022273. The next prime is 1014132022427. The reversal of 1014132022403 is 3042202314101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1014132022403 - 28 = 1014132022147 is a prime.

It is a super-3 number, since 3×10141320224033 (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1014132222403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7622576 + ... + 7754477.

It is an arithmetic number, because the mean of its divisors is an integer number (253536866352).

Almost surely, 21014132022403 is an apocalyptic number.

1014132022403 is a deficient number, since it is larger than the sum of its proper divisors (15443005).

1014132022403 is an equidigital number, since it uses as much as digits as its factorization.

1014132022403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15443004.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1014132022403 its reverse (3042202314101), we get a palindrome (4056334336504).

The spelling of 1014132022403 in words is "one trillion, fourteen billion, one hundred thirty-two million, twenty-two thousand, four hundred three".

Divisors: 1 65951 15377053 1014132022403