Base | Representation |
---|---|
bin | 10010111100100110… |
… | …10100110000010001 |
3 | 222020220112010012122 |
4 | 21132103110300101 |
5 | 131313021334031 |
6 | 4401210304025 |
7 | 510034033433 |
oct | 113623246021 |
9 | 28226463178 |
10 | 10172058641 |
11 | 434a953238 |
12 | 1b7a728015 |
13 | c61540814 |
14 | 6c6d50653 |
15 | 3e804847b |
hex | 25e4d4c11 |
10172058641 has 2 divisors, whose sum is σ = 10172058642. Its totient is φ = 10172058640.
The previous prime is 10172058587. The next prime is 10172058643. The reversal of 10172058641 is 14685027101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10040841616 + 131217025 = 100204^2 + 11455^2 .
It is a cyclic number.
It is not a de Polignac number, because 10172058641 - 222 = 10167864337 is a prime.
Together with 10172058643, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10172058643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5086029320 + 5086029321.
It is an arithmetic number, because the mean of its divisors is an integer number (5086029321).
Almost surely, 210172058641 is an apocalyptic number.
It is an amenable number.
10172058641 is a deficient number, since it is larger than the sum of its proper divisors (1).
10172058641 is an equidigital number, since it uses as much as digits as its factorization.
10172058641 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 35.
The spelling of 10172058641 in words is "ten billion, one hundred seventy-two million, fifty-eight thousand, six hundred forty-one".
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