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102022001113 is a prime number
BaseRepresentation
bin101111100000011111…
…1000011000111011001
3100202100002101122022211
41133000333003013121
53132420113013423
6114511313315121
710241125462324
oct1370077030731
9322302348284
10102022001113
113a2a383a4aa
1217932b65aa1
13980b6bacc6
144d1b8057bb
1529c19e610d
hex17c0fc31d9

102022001113 has 2 divisors, whose sum is σ = 102022001114. Its totient is φ = 102022001112.

The previous prime is 102022001089. The next prime is 102022001141. The reversal of 102022001113 is 311100220201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 63954869449 + 38067131664 = 252893^2 + 195108^2 .

It is a cyclic number.

It is not a de Polignac number, because 102022001113 - 213 = 102021992921 is a prime.

It is a super-2 number, since 2×1020220011132 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 102022001093 and 102022001102.

It is not a weakly prime, because it can be changed into another prime (102022001143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51011000556 + 51011000557.

It is an arithmetic number, because the mean of its divisors is an integer number (51011000557).

Almost surely, 2102022001113 is an apocalyptic number.

It is an amenable number.

102022001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

102022001113 is an equidigital number, since it uses as much as digits as its factorization.

102022001113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 102022001113 its reverse (311100220201), we get a palindrome (413122221314).

The spelling of 102022001113 in words is "one hundred two billion, twenty-two million, one thousand, one hundred thirteen".