Base | Representation |
---|---|
bin | 1001010010010011010000… |
… | …0101100000001000000011 |
3 | 1100011001211020012112101212 |
4 | 2110210310011200020003 |
5 | 2314240100321321011 |
6 | 33414225300120335 |
7 | 2102435410406414 |
oct | 224446405401003 |
9 | 40131736175355 |
10 | 10210011120131 |
11 | 3287050114a19 |
12 | 118a9280960ab |
13 | 590a52559504 |
14 | 27424aa2980b |
15 | 12a8bc22008b |
hex | 94934160203 |
10210011120131 has 2 divisors, whose sum is σ = 10210011120132. Its totient is φ = 10210011120130.
The previous prime is 10210011120041. The next prime is 10210011120143. The reversal of 10210011120131 is 13102111001201.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10210011120131 is a prime.
It is a super-2 number, since 2×102100111201312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10210011170131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105005560065 + 5105005560066.
It is an arithmetic number, because the mean of its divisors is an integer number (5105005560066).
Almost surely, 210210011120131 is an apocalyptic number.
10210011120131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10210011120131 is an equidigital number, since it uses as much as digits as its factorization.
10210011120131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 10210011120131 its reverse (13102111001201), we get a palindrome (23312122121332).
The spelling of 10210011120131 in words is "ten trillion, two hundred ten billion, eleven million, one hundred twenty thousand, one hundred thirty-one".
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