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102112112153 is a prime number
BaseRepresentation
bin101111100011001011…
…0110010111000011001
3100202120100221202102202
41133012112302320121
53133111200042103
6114524252535545
710243301426612
oct1370626627031
9322510852382
10102112112153
113a33a697237
12179591815b5
13982427b64c
144d29780c09
1529c9895988
hex17c65b2e19

102112112153 has 2 divisors, whose sum is σ = 102112112154. Its totient is φ = 102112112152.

The previous prime is 102112112033. The next prime is 102112112189. The reversal of 102112112153 is 351211211201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61728396304 + 40383715849 = 248452^2 + 200957^2 .

It is an emirp because it is prime and its reverse (351211211201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102112112153 - 212 = 102112108057 is a prime.

It is not a weakly prime, because it can be changed into another prime (102112162153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51056056076 + 51056056077.

It is an arithmetic number, because the mean of its divisors is an integer number (51056056077).

Almost surely, 2102112112153 is an apocalyptic number.

It is an amenable number.

102112112153 is a deficient number, since it is larger than the sum of its proper divisors (1).

102112112153 is an equidigital number, since it uses as much as digits as its factorization.

102112112153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 20.

Adding to 102112112153 its reverse (351211211201), we get a palindrome (453323323354).

The spelling of 102112112153 in words is "one hundred two billion, one hundred twelve million, one hundred twelve thousand, one hundred fifty-three".