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10221200113 is a prime number
BaseRepresentation
bin10011000010011101…
…10010001011110001
3222101022222202122011
421201032302023301
5131413111400423
64410123442521
7511201524145
oct114116621361
928338882564
1010221200113
114375667a23
121b93086441
13c6b788207
146cd6a3225
153ec503b0d
hex2613b22f1

10221200113 has 2 divisors, whose sum is σ = 10221200114. Its totient is φ = 10221200112.

The previous prime is 10221200111. The next prime is 10221200131. The reversal of 10221200113 is 31100212201.

Together with next prime (10221200131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9652473009 + 568727104 = 98247^2 + 23848^2 .

It is a cyclic number.

It is not a de Polignac number, because 10221200113 - 21 = 10221200111 is a prime.

Together with 10221200111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 10221200093 and 10221200102.

It is not a weakly prime, because it can be changed into another prime (10221200111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5110600056 + 5110600057.

It is an arithmetic number, because the mean of its divisors is an integer number (5110600057).

Almost surely, 210221200113 is an apocalyptic number.

It is an amenable number.

10221200113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10221200113 is an equidigital number, since it uses as much as digits as its factorization.

10221200113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10221200113 its reverse (31100212201), we get a palindrome (41321412314).

The spelling of 10221200113 in words is "ten billion, two hundred twenty-one million, two hundred thousand, one hundred thirteen".