Base | Representation |
---|---|
bin | 11101111110101101110… |
… | …00011011101001111111 |
3 | 10122110212121012202212121 |
4 | 32333112320123221333 |
5 | 113334122142120221 |
6 | 2105120015143411 |
7 | 134264616043306 |
oct | 16772670335177 |
9 | 3573777182777 |
10 | 1030102301311 |
11 | 367955992466 |
12 | 147783214b67 |
13 | 761a48cba55 |
14 | 37c002c143d |
15 | 1bbde34ba41 |
hex | efd6e1ba7f |
1030102301311 has 4 divisors (see below), whose sum is σ = 1031709325824. Its totient is φ = 1028495276800.
The previous prime is 1030102301273. The next prime is 1030102301359. The reversal of 1030102301311 is 1131032010301.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1030102301311 is a prime.
It is a super-2 number, since 2×10301023013112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1030102301611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 803511295 + ... + 803512576.
It is an arithmetic number, because the mean of its divisors is an integer number (257927331456).
Almost surely, 21030102301311 is an apocalyptic number.
1030102301311 is a deficient number, since it is larger than the sum of its proper divisors (1607024513).
1030102301311 is an equidigital number, since it uses as much as digits as its factorization.
1030102301311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1607024512.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1030102301311 its reverse (1131032010301), we get a palindrome (2161134311612).
The spelling of 1030102301311 in words is "one trillion, thirty billion, one hundred two million, three hundred one thousand, three hundred eleven".
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