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10301113012133 is a prime number
BaseRepresentation
bin1001010111100110101000…
…1011101000111110100101
31100110202222021111011012002
42111321222023220332211
52322233134412342013
633524133241535045
72112142116616166
oct225715213507645
940422867434162
1010301113012133
11331174a822859
1211a4511aa4485
13599510742698
1427880ddd976d
1512ce501a8358
hex95e6a2e8fa5

10301113012133 has 2 divisors, whose sum is σ = 10301113012134. Its totient is φ = 10301113012132.

The previous prime is 10301113012111. The next prime is 10301113012171. The reversal of 10301113012133 is 33121031110301.

Adding to 10301113012133 its reverse (33121031110301), we get a palindrome (43422144122434).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6932151878404 + 3368961133729 = 2632898^2 + 1835473^2 .

It is a cyclic number.

It is not a de Polignac number, because 10301113012133 - 212 = 10301113008037 is a prime.

It is a super-2 number, since 2×103011130121332 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10301113212133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5150556506066 + 5150556506067.

It is an arithmetic number, because the mean of its divisors is an integer number (5150556506067).

Almost surely, 210301113012133 is an apocalyptic number.

It is an amenable number.

10301113012133 is a deficient number, since it is larger than the sum of its proper divisors (1).

10301113012133 is an equidigital number, since it uses as much as digits as its factorization.

10301113012133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

The spelling of 10301113012133 in words is "ten trillion, three hundred one billion, one hundred thirteen million, twelve thousand, one hundred thirty-three".