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10302132113 = 713409127673
BaseRepresentation
bin10011001100000111…
…00000111110010001
3222120222021112110122
421212003200332101
5132044321211423
64422134240025
7513203451410
oct114603407621
928528245418
1010302132113
114407315379
121bb61b6015
13c82483880
146da32d477
1540468d8c8
hex2660e0f91

10302132113 has 16 divisors (see below), whose sum is σ = 12683104896. Its totient is φ = 8148850560.

The previous prime is 10302132109. The next prime is 10302132119. The reversal of 10302132113 is 31123120301.

It is a cyclic number.

It is not a de Polignac number, because 10302132113 - 22 = 10302132109 is a prime.

It is a super-2 number, since 2×103021321132 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10302132091 and 10302132100.

It is not an unprimeable number, because it can be changed into a prime (10302132119) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 358445 + ... + 386117.

It is an arithmetic number, because the mean of its divisors is an integer number (792694056).

Almost surely, 210302132113 is an apocalyptic number.

10302132113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

10302132113 is a deficient number, since it is larger than the sum of its proper divisors (2380972783).

10302132113 is a wasteful number, since it uses less digits than its factorization.

10302132113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31784.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 10302132113 its reverse (31123120301), we get a palindrome (41425252414).

The spelling of 10302132113 in words is "ten billion, three hundred two million, one hundred thirty-two thousand, one hundred thirteen".

Divisors: 1 7 13 91 4091 27673 28637 53183 193711 359749 372281 2518243 113210243 792471701 1471733159 10302132113