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10320122013 = 34183903431
BaseRepresentation
bin10011001110010000…
…01001000010011101
3222122020010111222020
421213020021002131
5132113422401023
64424020010353
7513512406165
oct114710110235
928566114866
1010320122013
114416492463
1220002309b9
13c86112096
146dc8935a5
15406043de3
hex26720909d

10320122013 has 8 divisors (see below), whose sum is σ = 14095776576. Its totient is φ = 6712274400.

The previous prime is 10320122009. The next prime is 10320122063. The reversal of 10320122013 is 31022102301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10320122013 - 22 = 10320122009 is a prime.

It is a super-3 number, since 3×103201220133 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10320121983 and 10320122001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10320122063) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41951593 + ... + 41951838.

It is an arithmetic number, because the mean of its divisors is an integer number (1761972072).

Almost surely, 210320122013 is an apocalyptic number.

It is an amenable number.

10320122013 is a deficient number, since it is larger than the sum of its proper divisors (3775654563).

10320122013 is an equidigital number, since it uses as much as digits as its factorization.

10320122013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83903475.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 10320122013 its reverse (31022102301), we get a palindrome (41342224314).

The spelling of 10320122013 in words is "ten billion, three hundred twenty million, one hundred twenty-two thousand, thirteen".

Divisors: 1 3 41 123 83903431 251710293 3440040671 10320122013