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10325004341341 is a prime number
BaseRepresentation
bin1001011000111111101000…
…1101110101000001011101
31100120001122022020102120211
42112033322031311001131
52323131102102410331
633543124100012421
72113646142562204
oct226177215650135
940501568212524
1010325004341341
11332089a862028
1211a907b091111
1359b84a380681
14279a3902823b
1512d89c8808b1
hex963fa37505d

10325004341341 has 2 divisors, whose sum is σ = 10325004341342. Its totient is φ = 10325004341340.

The previous prime is 10325004341317. The next prime is 10325004341357. The reversal of 10325004341341 is 14314340052301.

Adding to 10325004341341 its reverse (14314340052301), we get a palindrome (24639344393642).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6023441232900 + 4301563108441 = 2454270^2 + 2074021^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10325004341341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10325004348341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5162502170670 + 5162502170671.

It is an arithmetic number, because the mean of its divisors is an integer number (5162502170671).

Almost surely, 210325004341341 is an apocalyptic number.

It is an amenable number.

10325004341341 is a deficient number, since it is larger than the sum of its proper divisors (1).

10325004341341 is an equidigital number, since it uses as much as digits as its factorization.

10325004341341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

The spelling of 10325004341341 in words is "ten trillion, three hundred twenty-five billion, four million, three hundred forty-one thousand, three hundred forty-one".