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BaseRepresentation
bin1001011000111111101000…
…1101110101000001101101
31100120001122022020102121102
42112033322031311001231
52323131102102410412
633543124100012445
72113646142562226
oct226177215650155
940501568212542
1010325004341357
11332089a862042
1211a907b091125
1359b84a380694
14279a3902824d
1512d89c8808c2
hex963fa37506d

10325004341357 has 2 divisors, whose sum is σ = 10325004341358. Its totient is φ = 10325004341356.

The previous prime is 10325004341341. The next prime is 10325004341429. The reversal of 10325004341357 is 75314340052301.

Adding to 10325004341357 its reverse (75314340052301), we get a palindrome (85639344393658).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10194297508201 + 130706833156 = 3192851^2 + 361534^2 .

It is a cyclic number.

It is not a de Polignac number, because 10325004341357 - 24 = 10325004341341 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10325004341357.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10325004341317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5162502170678 + 5162502170679.

It is an arithmetic number, because the mean of its divisors is an integer number (5162502170679).

Almost surely, 210325004341357 is an apocalyptic number.

It is an amenable number.

10325004341357 is a deficient number, since it is larger than the sum of its proper divisors (1).

10325004341357 is an equidigital number, since it uses as much as digits as its factorization.

10325004341357 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 151200, while the sum is 38.

The spelling of 10325004341357 in words is "ten trillion, three hundred twenty-five billion, four million, three hundred forty-one thousand, three hundred fifty-seven".