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10354213131 = 37943688663
BaseRepresentation
bin10011010010010100…
…01100000100001011
3222201121021112012020
421221022030010023
5132201134310011
64431234415523
7514405234203
oct115112140413
928647245166
1010354213131
114433757639
12200b7315a3
13c901ba242
14703209403
1540902a006
hex26928c10b

10354213131 has 8 divisors (see below), whose sum is σ = 13980372480. Its totient is φ = 6815431272.

The previous prime is 10354213109. The next prime is 10354213141. The reversal of 10354213131 is 13131245301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10354213131 - 27 = 10354213003 is a prime.

It is a super-3 number, since 3×103542131313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (10354213141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21844095 + ... + 21844568.

It is an arithmetic number, because the mean of its divisors is an integer number (1747546560).

Almost surely, 210354213131 is an apocalyptic number.

10354213131 is a deficient number, since it is larger than the sum of its proper divisors (3626159349).

10354213131 is an equidigital number, since it uses as much as digits as its factorization.

10354213131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43688745.

The product of its (nonzero) digits is 1080, while the sum is 24.

Adding to 10354213131 its reverse (13131245301), we get a palindrome (23485458432).

The spelling of 10354213131 in words is "ten billion, three hundred fifty-four million, two hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 3 79 237 43688663 131065989 3451404377 10354213131