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10500310315 = 511291765449
BaseRepresentation
bin10011100011101111…
…00000010100101011
31000002210012000212001
421301313200110223
5133001034412230
64453534031431
7521131110415
oct116167402453
930083160761
1010500310315
1144a9173610
122050648577
13cb4550891
147187999b5
15416c880ca
hex271de052b

10500310315 has 16 divisors (see below), whose sum is σ = 13750783200. Its totient is φ = 7633854720.

The previous prime is 10500310273. The next prime is 10500310333. The reversal of 10500310315 is 51301300501.

10500310315 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10500310315 - 29 = 10500309803 is a prime.

It is a super-2 number, since 2×105003103152 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10500310292 and 10500310301.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 127711 + ... + 193159.

It is an arithmetic number, because the mean of its divisors is an integer number (859423950).

Almost surely, 210500310315 is an apocalyptic number.

10500310315 is a deficient number, since it is larger than the sum of its proper divisors (3250472885).

10500310315 is a wasteful number, since it uses less digits than its factorization.

10500310315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68382.

The product of its (nonzero) digits is 225, while the sum is 19.

Adding to 10500310315 its reverse (51301300501), we get a palindrome (61801610816).

The spelling of 10500310315 in words is "ten billion, five hundred million, three hundred ten thousand, three hundred fifteen".

Divisors: 1 5 11 55 2917 14585 32087 65449 160435 327245 719939 3599695 190914733 954573665 2100062063 10500310315