Base | Representation |
---|---|
bin | 11110100101111000100… |
… | …00000000000001000011 |
3 | 10201111011002011101000112 |
4 | 33102330100000001003 |
5 | 114210203331044303 |
6 | 2122514350541535 |
7 | 135640663253021 |
oct | 17227420000103 |
9 | 3644132141015 |
10 | 1051130331203 |
11 | 37586673a567 |
12 | 14b8715078ab |
13 | 78176278ba4 |
14 | 38c36d2d711 |
15 | 1c5204840d8 |
hex | f4bc400043 |
1051130331203 has 2 divisors, whose sum is σ = 1051130331204. Its totient is φ = 1051130331202.
The previous prime is 1051130331193. The next prime is 1051130331217. The reversal of 1051130331203 is 3021330311501.
It is a weak prime.
It is an emirp because it is prime and its reverse (3021330311501) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1051130331203 - 28 = 1051130330947 is a prime.
It is a super-2 number, since 2×10511303312032 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1051132331203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525565165601 + 525565165602.
It is an arithmetic number, because the mean of its divisors is an integer number (525565165602).
Almost surely, 21051130331203 is an apocalyptic number.
1051130331203 is a deficient number, since it is larger than the sum of its proper divisors (1).
1051130331203 is an equidigital number, since it uses as much as digits as its factorization.
1051130331203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 1051130331203 its reverse (3021330311501), we get a palindrome (4072460642704).
The spelling of 1051130331203 in words is "one trillion, fifty-one billion, one hundred thirty million, three hundred thirty-one thousand, two hundred three".
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