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1053412313314 = 2526706156657
BaseRepresentation
bin11110101010001000100…
…01000100100011100010
310201201001010010001222111
433111010101010203202
5114224342023011224
62123533025425534
7136051352632054
oct17250421044342
93651033101874
101053412313314
11376827874499
121501a979b2aa
137844ac82b6a
1438db202b8d4
151c605996d94
hexf5444448e2

1053412313314 has 4 divisors (see below), whose sum is σ = 1580118469974. Its totient is φ = 526706156656.

The previous prime is 1053412313311. The next prime is 1053412313357. The reversal of 1053412313314 is 4133132143501.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 664441807689 + 388970505625 = 815133^2 + 623675^2 .

It is a super-2 number, since 2×10534123133142 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1053412313311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 263353078327 + ... + 263353078330.

Almost surely, 21053412313314 is an apocalyptic number.

1053412313314 is a deficient number, since it is larger than the sum of its proper divisors (526706156660).

1053412313314 is an equidigital number, since it uses as much as digits as its factorization.

1053412313314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 526706156659.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 1053412313314 its reverse (4133132143501), we get a palindrome (5186544456815).

The spelling of 1053412313314 in words is "one trillion, fifty-three billion, four hundred twelve million, three hundred thirteen thousand, three hundred fourteen".

Divisors: 1 2 526706156657 1053412313314