Base | Representation |
---|---|
bin | 1010000000010010001111… |
… | …0000010000111110110011 |
3 | 1102221120221200112121202121 |
4 | 2200010203300100332303 |
5 | 2420211010320200313 |
6 | 35221200233255111 |
7 | 2213503346424145 |
oct | 240044360207663 |
9 | 42846850477677 |
10 | 11000011100083 |
11 | 3561095550635 |
12 | 1297a61564497 |
13 | 61a3b180c555 |
14 | 2a0590c24c95 |
15 | 14120764d28d |
hex | a0123c10fb3 |
11000011100083 has 2 divisors, whose sum is σ = 11000011100084. Its totient is φ = 11000011100082.
The previous prime is 11000011099999. The next prime is 11000011100087. The reversal of 11000011100083 is 38000111000011.
It is a strong prime.
It is an emirp because it is prime and its reverse (38000111000011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11000011100083 - 217 = 11000010969011 is a prime.
It is not a weakly prime, because it can be changed into another prime (11000011100087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500005550041 + 5500005550042.
It is an arithmetic number, because the mean of its divisors is an integer number (5500005550042).
Almost surely, 211000011100083 is an apocalyptic number.
11000011100083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000011100083 is an equidigital number, since it uses as much as digits as its factorization.
11000011100083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 11000011100083 its reverse (38000111000011), we get a palindrome (49000122100094).
The spelling of 11000011100083 in words is "eleven trillion, eleven million, one hundred thousand, eighty-three".
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