11000100000047 has 2 divisors, whose sum is σ = 11000100000048. Its totient is φ = 11000100000046.

The previous prime is 11000100000007. The next prime is 11000100000121. The reversal of 11000100000047 is 74000000100011.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11000100000047 is a prime.

It is a super-2 number, since 2×11000100000047² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11000099999977 and 11000100000040.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000100000007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500050000023 + 5500050000024.

It is an arithmetic number, because the mean of its divisors is an integer number (5500050000024).

Almost surely, 2^{11000100000047} is an apocalyptic number.

11000100000047 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000100000047 is an equidigital number, since it uses as much as digits as its factorization.

11000100000047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28, while the sum is 14.

Adding to 11000100000047 its reverse (74000000100011), we get a palindrome (85000100100058).

The spelling of 11000100000047 in words is "eleven trillion, one hundred million, forty-seven", and thus it is an aban number.