1100013312133 has 2 divisors, whose sum is σ = 1100013312134. Its totient is φ = 1100013312132.

The previous prime is 1100013312091. The next prime is 1100013312143. The reversal of 1100013312133 is 3312133100011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1052097415524 + 47915896609 = 1025718^2 + 218897^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100013312133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1100013312133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100013312143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006656066 + 550006656067.

It is an arithmetic number, because the mean of its divisors is an integer number (550006656067).

Almost surely, 2^{1100013312133} is an apocalyptic number.

It is an amenable number.

1100013312133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100013312133 is an equidigital number, since it uses as much as digits as its factorization.

1100013312133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1100013312133 its reverse (3312133100011), we get a palindrome (4412146412144).

The spelling of 1100013312133 in words is "one trillion, one hundred billion, thirteen million, three hundred twelve thousand, one hundred thirty-three".