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1100020133 is a prime number
BaseRepresentation
bin100000110010000…
…1111100110100101
32211122212210221102
41001210033212211
54223101121013
6301053125445
736155005532
oct10144174645
92748783842
101100020133
11514a29453
12268489885
13146b89bb4
14a6145d89
156688bd58
hex4190f9a5

1100020133 has 2 divisors, whose sum is σ = 1100020134. Its totient is φ = 1100020132.

The previous prime is 1100020127. The next prime is 1100020177. The reversal of 1100020133 is 3310200011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 823862209 + 276157924 = 28703^2 + 16618^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100020133 - 212 = 1100016037 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100020433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550010066 + 550010067.

It is an arithmetic number, because the mean of its divisors is an integer number (550010067).

Almost surely, 21100020133 is an apocalyptic number.

It is an amenable number.

1100020133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100020133 is an equidigital number, since it uses as much as digits as its factorization.

1100020133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 1100020133 is about 33166.5514185602. The cubic root of 1100020133 is about 1032.2864132651.

Adding to 1100020133 its reverse (3310200011), we get a palindrome (4410220144).

The spelling of 1100020133 in words is "one billion, one hundred million, twenty thousand, one hundred thirty-three".