Base | Representation |
---|---|
bin | 10000000000011110011… |
… | …111111011001011100010 |
3 | 10220011100111221012022201 |
4 | 100000132133323023202 |
5 | 121010321432004442 |
6 | 2201202125123414 |
7 | 142321413612556 |
oct | 20003637731342 |
9 | 3804314835281 |
10 | 1100023313122 |
11 | 394576534538 |
12 | 1592376b956a |
13 | 7c96887b716 |
14 | 3b354615866 |
15 | 1d932a587b7 |
hex | 1001e7fb2e2 |
1100023313122 has 4 divisors (see below), whose sum is σ = 1650034969686. Its totient is φ = 550011656560.
The previous prime is 1100023313117. The next prime is 1100023313143. The reversal of 1100023313122 is 2213133200011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 897758145001 + 202265168121 = 947501^2 + 449739^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 1100023313122.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275005828279 + ... + 275005828282.
Almost surely, 21100023313122 is an apocalyptic number.
1100023313122 is a deficient number, since it is larger than the sum of its proper divisors (550011656564).
1100023313122 is an equidigital number, since it uses as much as digits as its factorization.
1100023313122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 550011656563.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1100023313122 its reverse (2213133200011), we get a palindrome (3313156513133).
The spelling of 1100023313122 in words is "one trillion, one hundred billion, twenty-three million, three hundred thirteen thousand, one hundred twenty-two".
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