11001000000953 has 2 divisors, whose sum is σ = 11001000000954. Its totient is φ = 11001000000952.

The previous prime is 11001000000923. The next prime is 11001000000959. The reversal of 11001000000953 is 35900000010011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8367088478464 + 2633911522489 = 2892592^2 + 1622933^2 .

It is an emirp because it is prime and its reverse (35900000010011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001000000953 - 2²⁸ = 11000731565497 is a prime.

It is not a weakly prime, because it can be changed into another prime (11001000000959) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500500000476 + 5500500000477.

It is an arithmetic number, because the mean of its divisors is an integer number (5500500000477).

Almost surely, 2^{11001000000953} is an apocalyptic number.

It is an amenable number.

11001000000953 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001000000953 is an equidigital number, since it uses as much as digits as its factorization.

11001000000953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135, while the sum is 20.

Adding to 11001000000953 its reverse (35900000010011), we get a palindrome (46901000010964).

The spelling of 11001000000953 in words is "eleven trillion, one billion, nine hundred fifty-three", and thus it is an aban number.