Search a number
BaseRepresentation
bin1010000000010101111010…
…1100100111111000111001
31102221200111121022222220111
42200011132230213320321
52420220022000013311
635221442321024321
72213540015100346
oct240053654477071
942850447288814
1011001000001081
113561552783592
1212980987850a1
1361a50b66187c
142a06462c37cd
hexa015eb27e39

11001000001081 has 2 divisors, whose sum is σ = 11001000001082. Its totient is φ = 11001000001080.

The previous prime is 11001000001063. The next prime is 11001000001127. The reversal of 11001000001081 is 18010000010011.

Adding to 11001000001081 its reverse (18010000010011), we get a palindrome (29011000011092).

11001000001081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10793136954681 + 207863046400 = 3285291^2 + 455920^2 .

It is a cyclic number.

It is not a de Polignac number, because 11001000001081 - 27 = 11001000000953 is a prime.

It is a super-2 number, since 2×110010000010812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11001000001181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500500000540 + 5500500000541.

It is an arithmetic number, because the mean of its divisors is an integer number (5500500000541).

Almost surely, 211001000001081 is an apocalyptic number.

It is an amenable number.

11001000001081 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001000001081 is an equidigital number, since it uses as much as digits as its factorization.

11001000001081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 13.

The spelling of 11001000001081 in words is "eleven trillion, one billion, one thousand, eighty-one".