Base | Representation |
---|---|
bin | 11001000000110110110011… |
… | …100100110000110010101011 |
3 | 112102111212001202100010010101 |
4 | 121000312303210300302223 |
5 | 103404401000042024042 |
6 | 1025545522335130231 |
7 | 32112650414203216 |
oct | 3100666344606253 |
9 | 472455052303111 |
10 | 110010010111147 |
11 | 32063a8a830923 |
12 | 10408815973977 |
13 | 494cb900bbc53 |
14 | 1d2472757677d |
15 | cab92d41b6b7 |
hex | 640db3930cab |
110010010111147 has 2 divisors, whose sum is σ = 110010010111148. Its totient is φ = 110010010111146.
The previous prime is 110010010111063. The next prime is 110010010111151. The reversal of 110010010111147 is 741111010010011.
It is a strong prime.
It is an emirp because it is prime and its reverse (741111010010011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110010010111147 - 211 = 110010010109099 is a prime.
It is not a weakly prime, because it can be changed into another prime (110010010111187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005005055573 + 55005005055574.
It is an arithmetic number, because the mean of its divisors is an integer number (55005005055574).
Almost surely, 2110010010111147 is an apocalyptic number.
110010010111147 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010010111147 is an equidigital number, since it uses as much as digits as its factorization.
110010010111147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 19.
Adding to 110010010111147 its reverse (741111010010011), we get a palindrome (851121020121158).
The spelling of 110010010111147 in words is "one hundred ten trillion, ten billion, ten million, one hundred eleven thousand, one hundred forty-seven".
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